0.005x^2+0.02x-2=0

Solution for 0.005x^2+0.02x-2=0 equation:

0.005x^2+0.02x-2=0

a = 0.005; b = 0.02; c = -2;
Δ = b2-4ac
Δ = 0.022-4·0.005·(-2)
Δ = 0.0404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.02)-\sqrt{0.0404}}{2*0.005}=\frac{-0.02-\sqrt{0.0404}}{0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.02)+\sqrt{0.0404}}{2*0.005}=\frac{-0.02+\sqrt{0.0404}}{0.01}
$